Guide

Expanding a single bracket

By Viktor Lassen4 min readUpdated 3 September 2026

The sign in front of a bracket decides how we open it. A multiplication in front means we multiply into the bracket, so 3 ร— (2x + 3y) = 6x + 9y. A minus in front means we flip the signs of everything inside.

Brackets are the top step of the order of operations, so they're also what we deal with first when we work out a calculation or solve an equation. The sign in front of the bracket, ++, โˆ’- or ร—\times, decides what kind of bracket it is, and so how we open it. (Opening a bracket just means working it out.) The typical hurdle is a bracket with letters inside, because then we can't simply work out what's in it.

When do I use this?

Whenever a bracket is in the way. In the exam this is called expanding the bracket, and there are three cases, depending on the sign in front.

With a plus in front, like

3+(3+2)3 + (3 + 2)

we can just work out what's inside the bracket. There's nothing special to take into account. With a multiplication or a minus in front we have to do it differently, and that's what this guide is about. Where brackets sit among the other operations is in order of operations.

Multiplication brackets: multiply into the bracket

A bracket with a multiplication sign in front, like this one:

3ร—(2x+3y)3 \times (2x + 3y)

Here we're forced to multiply into the bracket, which means we multiply 3 with both terms in the bracket. In the book there are two arrows from the 3, one to each term, and each arrow is a multiplication. So:

3ร—2xand3ร—3y3 \times 2x \quad \text{and} \quad 3 \times 3y

6x+9y6x + 9y

Expanding a single bracket: 3 ร— (2x + 3y) = 6x + 9y

So when we can't work out what's inside the bracket, we have to multiply into it.

If there had only been numbers inside the bracket, like

3ร—(2+3)3 \times (2 + 3)

we could easily have worked out the bracket first and then multiplied by 3. We'd add 2 and 3:

3ร—(5)3 \times (5)

and then multiply:

3ร—5=153 \times 5 = 15

If we had multiplied into the bracket instead, we would have said

3ร—2+3ร—3=153 \times 2 + 3 \times 3 = 15

We multiply 3 by 2, and then 3 by 3. It gives us the same result. So with only numbers inside, both ways work. It's when we can't work out or simplify what's inside the bracket that we're forced to multiply in.

Minus brackets: flip the signs

3โˆ’(2+3)3 - (2 + 3)

This is a minus bracket, because there's a minus in front. Here we could easily start by working out what's inside the bracket and then subtract it from 3. But when the bracket gets more complicated, we have to do it another way. We have to flip the signs, the plus and minus, on all the terms inside the bracket:

3โˆ’(2x+3y)3 - (2x + 3y)

2x2x turns into โˆ’2x-2x, and +3y+3y turns into โˆ’3y-3y. Remember that there's also an invisible plus in front of 2x2x. That's exactly why it becomes โˆ’2x-2x.

3โˆ’2xโˆ’3y3 - 2x - 3y

It can seem strange to flip the signs, but there's a good reason for it. A bracket, or anything else, can always be written with 1ร—1 \times in front, since the bracket is there 1 time. So we can also write this example as

3โˆ’1ร—(2x+3y)3 - 1 \times (2x + 3y)

Here we can see that we have a multiplication bracket with โˆ’1-1. When we multiply โˆ’1-1 into the bracket, we see that the signs inside the bracket simply flip:

3+(โˆ’2x)โˆ’3y3 + (-2x) - 3y

So that's why we can just flip the signs when we open minus brackets.

Worked examples

A multiplication bracket with letters. Expand 3ร—(2x+3y)3 \times (2x + 3y).

Multiply the 3 with both terms: 3ร—2x=6x3 \times 2x = 6x and 3ร—3y=9y3 \times 3y = 9y.

3ร—(2x+3y)=6x+9y3 \times (2x + 3y) = 6x + 9y

A multiplication bracket with only numbers. Work out 3ร—(2+3)3 \times (2 + 3).

Either way works. Inside first: 3ร—5=153 \times 5 = 15. Multiplying in: 3ร—2+3ร—3=6+9=153 \times 2 + 3 \times 3 = 6 + 9 = 15.

A minus bracket. Expand 3โˆ’(2x+3y)3 - (2x + 3y).

Flip every sign inside: 2x2x becomes โˆ’2x-2x, +3y+3y becomes โˆ’3y-3y.

3โˆ’(2x+3y)=3โˆ’2xโˆ’3y3 - (2x + 3y) = 3 - 2x - 3y

We can check this is right, because we know a bracket can be written with 1ร—1 \times in front, and โˆ’1-1 multiplied into (2x+3y)(2x + 3y) gives โˆ’2xโˆ’3y-2x - 3y.

Common mistakes

  • "Work out the inside of the bracket first, even when there are letters in it." You can't. 2x+3y2x + 3y isn't a single number, so there's nothing to work out. That's the whole reason we multiply into the bracket.
  • "Forgetting the invisible plus." In 3โˆ’(2x+3y)3 - (2x + 3y) there's an invisible ++ in front of the 2x2x. Flip it, and 2x2x becomes โˆ’2x-2x. Forget it, and you'll leave the 2x2x positive.
  • "The sign flip is magic." It isn't. 3โˆ’(2x+3y)3 - (2x + 3y) is 3โˆ’1ร—(2x+3y)3 - 1 \times (2x + 3y), a multiplication bracket with โˆ’1-1, and multiplying โˆ’1-1 in is what flips the signs.
  • "Plus brackets need special treatment." They don't. 3+(3+2)3 + (3 + 2) is just 3+53 + 5.

Brackets are the top of the pyramid in order of operations, and once a bracket is open you usually finish by collecting like terms. Two brackets multiplied together, like (x+1)(xโˆ’2)(x + 1)(x - 2), follow the same idea one step further, see expanding double brackets. The overview lives in simplifying expressions.

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